夏玉米不同部位干物质临界氮浓度稀释曲线的构建及对产量的估计

苏文楠, 解君, 韩娟, 刘铁宁, 韩清芳

Construction of critical nitrogen dilution curve based on dry matter in diffe rent organs of summer maize and estimation of grain yield

SU Wen-Nan, XIE Jun, HAN Juan, LIU Tie-Ning, HAN Qing-Fang

表5 V12和VT时期氮营养指数(NNI)和累积氮亏缺(AND)的相对产量(RY)的预测模型(根据4年试验数据估算)

Table 5 Prediction models for estimation of relative yield (RY) from nitrogen nutrition index (NNI) and accumulated nitrogen deficit (AND) at V12 and VT stage using pooled data of four years

处理 Treatment 生育时期 Growth stage R2 回归方程 Regression equation (RY-AND) R2 回归方程 Regression equation (RY-NNI) ZD leaf V12 0.94 RY = 1.081-0.026AND if AND > 3.5 and RY = 0.99 AND ≤ 3.5 0.96 RY = -0.01+NNI if NNI<0.95 and RY = 0.99 NNI ≥ 0.95 VT 0.95 RY = 1.138-0.028AND if AND > 5.3 and RY = 0.99 AND ≤ 5.3 0.96 RY = -0.033+1.1NNI if NNI<0.93 and RY = 0.99 NNI ≥ 0.93 SD leaf V12 0.98 RY = 1.010-0.019AND if AND > 0.5 and RY = 1 AND ≤ 0.5 0.98 RY = 0.284+0.688NNI if NNI<1.04 and RY = 1 NNI ≥ 1.04 VT 0.98 RY = 0.997-0.017AND if AND > 0.4 and RY = 0.99 AND ≤ 0.4 0.98 RY = 0.271+0.705NNI if NNI<1.02 and RY = 0.99 NNI ≥ 1.02 ZD stem V12 0.97 RY = 1.079-0.023AND if AND > 3.6 and RY = 0.99 AND ≤ 3.6 0.97 RY = 0.418+0.615NNI if NNI<0.93 and RY = 0.99 NNI ≥ 0.93 VT 0.98 RY = 1.182-0.024AND if AND > 8 and RY = 0.99 AND ≤ 8 0.98 RY = 0.414+0.678NNI if NNI<0.85 and RY = 0.99 NNI ≥ 0.85 SD stem V12 0.98 RY = 1.014-0.016AND if AND > 1.5 and RY = 0.99 AND ≤ 1.5 0.98 RY = 0.494+0.506NNI if NNI<1 and RY = 1 NNI ≥ 1 VT 0.98 RY = 1.006-0.01AND if AND > 1.6 and RY = 0.99 AND ≤ 1.6 0.99 RY = 0.565+0.405NNI if NNI < 1.05 and RY = 0.99 NNI ≥ 1.05 ZD plant V12 0.97 RY = 1.148-0.015AND if AND > 10.5 and RY = 0.99 AND ≤ 10.5 0.97 RY = 0.188+0.881NNI if NNI < 0.91 and RY = 0.99 NNI ≥ 0.91 VT 0.98 RY = 1.072-0.01AND if AND > 8.2 and RY = 0.99 AND ≤ 8.2 0.98 RY = 0.139+0.886NNI if NNI < 0.96 and RY = 0.99 NNI ≥ 0.96 SD plant V12 0.98 RY = 1.048-0.01AND if AND > 4.8 and RY = 1 AND ≤ 4.8 0.99 RY = 0.351+0.669NNI if NNI < 0.97 and RY = 1 NNI ≥ 0.97 VT 0.98 RY = 1.013-0.005AND if AND > -4.6 and RY = 0.99 AND ≤ -4.6 0.98 RY = 0.412+0.556NNI if NNI < 1.06 and RY = 1 NNI ≥ 1.06